What is the limit as x approaches 0 of+(x^{sqrt(x)}) ?

The limit as x approaches 0 of+(x^{sqrt(x)}) is Does not exist

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limit as x approaches 0 of+(x^{sqrt(x)})

x \to 0 lim (+ (x^{x}))

Does not exist

Solution steps

x \to 0 lim (x^{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x^{x}) = 1

x \to 0 - lim (x^{x}) =

Does not exist

= Does not exist

x \to 0 lim (ln (x + 1))

x \to 5 - lim (\frac{- 2}{x - 5})

x \to 2 - lim (\frac{x}{x + 2})

x \to 0 lim (arctan (\frac{2}{x}))

x \to 4 lim (\frac{x ^{2} - 1}{x - 1})

What is the limit as x approaches 0 of+(x^{sqrt(x)}) ?
The limit as x approaches 0 of+(x^{sqrt(x)}) is Does not exist