What is the derivative of tan(x^x) ?

The derivative of tan(x^x) is sec^2(x^x)x^x(ln(x)+1)

What is the first derivative of tan(x^x) ?

The first derivative of tan(x^x) is sec^2(x^x)x^x(ln(x)+1)

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\frac{d}{d x} (tan (x^{x}))

sec^{2} (x^{x}) x^{x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (tan (x^{x}))

Apply the chain rule:

sec^{2} (x^{x}) \frac{d}{d x} (x^{x})

= sec^{2} (x^{x}) \frac{d}{d x} (x^{x})

\frac{d}{d x} (x^{x}) = x^{x} (ln (x) + 1)

= sec^{2} (x^{x}) x^{x} (ln (x) + 1)

3 x (x y - 2) d x + (x^{3} + 2 y) d y = 0

\frac{d}{d x} (x + x^{2} + x + \frac{6}{7 x ^{3}})

\int \frac{( 1 + x )}{x ^{2}} d x

\int cos^{5} (4 x) sin (4 x) d x

\frac{d}{d x} (ln (6 x^{2} + 2 x + 2))

What is the derivative of tan(x^x) ?
The derivative of tan(x^x) is sec^2(x^x)x^x(ln(x)+1)
What is the first derivative of tan(x^x) ?
The first derivative of tan(x^x) is sec^2(x^x)x^x(ln(x)+1)