What is the tangent of f(x)=(4x+3)/(x+1),\at x=3 ?

The tangent of f(x)=(4x+3)/(x+1),\at x=3 is y= 1/16 x+57/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(4x+3)/(x+1),\at x=3

tangent of

f (x) = \frac{4 x + 3}{x + 1}, at x = 3

y = \frac{1}{16} x + \frac{57}{16}

Solution steps

Find the tangent point:

(3, \frac{15}{4})

Find the slope of

f (x) = \frac{4 x + 3}{x + 1} : \frac{df ( x )}{d x} = \frac{1}{( x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{4 x + 3}{x + 1}

x = 3 : m = \frac{1}{16}

Find the line with slope m=

\frac{1}{16}

and passing through

(3, \frac{15}{4}) : y = \frac{1}{16} x + \frac{57}{16}

y = \frac{1}{16} x + \frac{57}{16}

\frac{d}{d x} ((arcsec (\frac{x ^{2}}{2}))^{3 x})

f (x) = - \frac{x}{2}

x + 5

y = 3 x, y = 4 x^{2}

y^{^{'}} = \frac{( x + y )}{x}

What is the tangent of f(x)=(4x+3)/(x+1),\at x=3 ?
The tangent of f(x)=(4x+3)/(x+1),\at x=3 is y= 1/16 x+57/16