What is the tangent of y= 1/(x^6),(2, 1/64) ?

The tangent of y= 1/(x^6),(2, 1/64) is y=-3/64 x+7/64

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tangent of y= 1/(x^6),(2, 1/64)

tangent of

y = \frac{1}{x ^{6}}, (2, \frac{1}{64})

y = - \frac{3}{64} x + \frac{7}{64}

Solution steps

Find the slope of

y = \frac{1}{x ^{6}} : \frac{d y}{d x} = - \frac{6}{x ^{7}}

Compute the slope of

y = \frac{1}{x ^{6}}

(2, \frac{1}{64}) : m = - \frac{3}{64}

Find the line with slope m=

- \frac{3}{64}

and passing through

(2, \frac{1}{64}) : y = - \frac{3}{64} x + \frac{7}{64}

y = - \frac{3}{64} x + \frac{7}{64}

\int 1 x^{3} d x

f (x) = \frac{6 x}{x ^{2} + 1}, (0, 0)

\int \frac{1}{48} x d x

f (x) = (x - 1)^{2} + 1, at x = 0

(1 + x^{2})^{\frac{1}{4}}

What is the tangent of y= 1/(x^6),(2, 1/64) ?
The tangent of y= 1/(x^6),(2, 1/64) is y=-3/64 x+7/64