What is the limit as x approaches 2 of ln(x-2)+pi/2 ?

The limit as x approaches 2 of ln(x-2)+pi/2 is Does not exist

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limit as x approaches 2 of ln(x-2)+pi/2

x \to 2 lim (ln (x - 2) + \frac{π}{2})

Does not exist

Solution steps

x \to 2 lim (ln (x - 2) + \frac{π}{2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (ln (x - 2) + \frac{π}{2}) = - \infty

x \to 2 - lim (ln (x - 2) + \frac{π}{2}) =

Does not exist

= Does not exist

x \to 4 + lim (4 - x)

x \to - 1 - lim (\frac{3 x - 5}{2 x - 2})

x \to 4 lim (x - 2)

x \to 1 - lim (\frac{x ^{2} - 4}{x - 1})

x \to 0 lim (\frac{f ( x )}{x ^{6}})

What is the limit as x approaches 2 of ln(x-2)+pi/2 ?
The limit as x approaches 2 of ln(x-2)+pi/2 is Does not exist