What is the derivative of f(x)=tan(2x) ?

The derivative of f(x)=tan(2x) is sec^2(2x)*2

What is the first derivative of f(x)=tan(2x) ?

The first derivative of f(x)=tan(2x) is sec^2(2x)*2

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derivative of

f (x) = tan (2 x)

sec^{2} (2 x) \cdot 2

Solution steps

\frac{d}{d x} (tan (2 x))

Apply the chain rule:

sec^{2} (2 x) \frac{d}{d x} (2 x)

= sec^{2} (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= sec^{2} (2 x) \cdot 2

\int - 4 sin^{3} (x) cos^{5} (x) d x

y = x^{2} - 4 x + 1, y = x + 1

x \to 0 lim (\frac{- x ^{- x} - 1}{x})

\frac{d}{d x} (\frac{e ^{- x}}{x - 5} + 1)

x \to 0 + lim ((1 + 2 x)^{\frac{4}{x}})

What is the derivative of f(x)=tan(2x) ?
The derivative of f(x)=tan(2x) is sec^2(2x)*2
What is the first derivative of f(x)=tan(2x) ?
The first derivative of f(x)=tan(2x) is sec^2(2x)*2