en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^2-4x+1,y=x+1

Solution

area

y = x^{2} - 4 x + 1, y = x + 1

Solution

\frac{125}{6}

+1

Decimal Notation

20.83333 \dots

Solution steps

Apply the area formula:

\int_{0}^{5} x^{2} - 4 x + 1 - (x + 1) d x

Solve

\int_{0}^{5} x^{2} - 4 x + 1 - (x + 1) d x : \frac{125}{6}

The area is:

= \frac{125}{6}

Popular Examples

limit as x approaches 0 of (-x^{-x}-1)/x

x \to 0 lim (\frac{- x ^{- x} - 1}{x})

derivative of (e^{-x}/(x-5)+1)

\frac{d}{d x} (\frac{e ^{- x}}{x - 5} + 1)

limit as x approaches 0+of (1+2x)^{4/x}

x \to 0 + lim ((1 + 2 x)^{\frac{4}{x}})

x^3(d^3y)/(dx^3)+2x^2(d^2y)/(dx^2)-x(dy)/(dx)+y=12x^2

x^{3} \frac{d ^{3} y}{d x ^{3}} + 2 x^{2} \frac{d ^{2} y}{d x ^{2}} - x \frac{d y}{d x} + y = 12 x^{2}

(d^3)/(dt^3)((t^2-1)^3)

\frac{d ^{3}}{d t ^{3}} ((t^{2} - 1)^{3})

Frequently Asked Questions (FAQ)

What is area y=x^2-4x+1,y=x+1 ?
The answer to area y=x^2-4x+1,y=x+1 is 125/6