What is the limit as x approaches 0 of+(x-1)/x ?

The limit as x approaches 0 of+(x-1)/x is diverges

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limit as x approaches 0 of+(x-1)/x

x \to 0 lim (+ \frac{x - 1}{x})

diverges

Solution steps

x \to 0 lim (\frac{x - 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{x - 1}{x}) = - \infty

x \to 0 - lim (\frac{x - 1}{x}) = \infty

= diverges

x \to 0 lim (x^{2} - 4 x)

x \to - \infty lim (e x)

x \to 0 lim (sin (\frac{1}{2 x}))

u \to 0 lim (\frac{sin ( u )}{u})

x \to 0 lim (sin^{x} (\frac{1}{x}))

What is the limit as x approaches 0 of+(x-1)/x ?
The limit as x approaches 0 of+(x-1)/x is diverges