What is the limit as x approaches 0 of ln(e+x) ?

The limit as x approaches 0 of ln(e+x) is 1

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limit as x approaches 0 of ln(e+x)

x \to 0 lim (ln (e + x))

1

Solution steps

x \to 0 lim (ln (e + x))

Plug in the value

x = 0

= ln (e + 0)

Simplify

ln (e + 0) : 1

= 1

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x \to 1 lim (\frac{2}{x} - \frac{1}{ln ( x )})

x \to \infty lim (4 - \frac{x}{2})

x \to - 5 lim (\frac{10}{x + 5})

x \to - 4 + lim (4 - x)

What is the limit as x approaches 0 of ln(e+x) ?
The limit as x approaches 0 of ln(e+x) is 1