What is the limit as x approaches 1 of (3x+1)/(x-1) ?

The limit as x approaches 1 of (3x+1)/(x-1) is diverges

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limit as x approaches 1 of (3x+1)/(x-1)

x \to 1 lim (\frac{3 x + 1}{x - 1})

diverges

Solution steps

x \to 1 lim (\frac{3 x + 1}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{3 x + 1}{x - 1}) = \infty

x \to 1 - lim (\frac{3 x + 1}{x - 1}) = - \infty

= diverges

x \to \infty lim (\frac{3 x + x ^{- 6}}{4 x - 4})

x \to 0 lim (x^{- 3} sin (3 x) + x^{- 2} a + b)

x \to 0 lim (\frac{e ^{x} + x - 1}{x})

x \to 0 lim (\frac{( 9 ^{x} - 4 ^{x} )}{x})

x \to 2 lim (4 (x - 4) (x - 2))

What is the limit as x approaches 1 of (3x+1)/(x-1) ?
The limit as x approaches 1 of (3x+1)/(x-1) is diverges