What is the limit as x approaches 4 of log_{5}(6x+1) ?

The limit as x approaches 4 of log_{5}(6x+1) is 2

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limit as x approaches 4 of log_{5}(6x+1)

x \to 4 lim (lo g_{5} (6 x + 1))

2

Solution steps

x \to 4 lim (lo g_{5} (6 x + 1))

Plug in the value

x = 4

= lo g_{5} (6 \cdot 4 + 1)

Simplify

lo g_{5} (6 \cdot 4 + 1) : 2

= 2

x \to 2 lim (12)

x \to \infty lim (\frac{3}{e ^{- x} + 2})

x \to 0 lim (5 ln (x))

x \to 0 lim (\frac{x + 1}{x ^{2}})

x \to 0 lim (2 x ln (x))

What is the limit as x approaches 4 of log_{5}(6x+1) ?
The limit as x approaches 4 of log_{5}(6x+1) is 2