What is (\partial)/(\partial x)(x^2+4) ?

The answer to (\partial)/(\partial x)(x^2+4) is 2x

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(\partial)/(\partial x)(x^2+4)

\frac{\partial}{\partial x} (x^{2} + 4)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (4) = 0

= 2 x + 0

Simplify

= 2 x

\frac{d}{d x} (ln (3 x^{2} + 1) ln (2 x^{3} + 1))

\int \frac{x ^{5} + x + 1}{x ^{3} - 8} d x

y = (x^{2} + 3) ((2 x + 5)^{6})

\frac{d}{d x} (5 + \frac{1}{x ^{2}})

\int_{0}^{3} x^{2} - 4 d x

What is (\partial)/(\partial x)(x^2+4) ?
The answer to (\partial)/(\partial x)(x^2+4) is 2x