What is the limit as x approaches 3 of (x^2+5)/(x-3) ?

The limit as x approaches 3 of (x^2+5)/(x-3) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 3 of (x^2+5)/(x-3)

x \to 3 lim (\frac{x ^{2} + 5}{x - 3})

diverges

Solution steps

x \to 3 lim (\frac{x ^{2} + 5}{x - 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x ^{2} + 5}{x - 3}) = \infty

x \to 3 - lim (\frac{x ^{2} + 5}{x - 3}) = - \infty

= diverges

x \to 3 lim (\frac{16}{4 - x ^{2}})

x \to 0 + lim (\frac{2}{x} - \frac{2}{x ^{2} + x})

x \to - \infty lim (x^{4} + 4 x)

x \to - 5 - lim (- \frac{3 x}{x + 5})

x \to 1 lim (\frac{5 x - 1}{x + 1})

What is the limit as x approaches 3 of (x^2+5)/(x-3) ?
The limit as x approaches 3 of (x^2+5)/(x-3) is diverges