What is the limit as x approaches-7-of (2x+1)/(x+7) ?

The limit as x approaches-7-of (2x+1)/(x+7) is infinity

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limit as x approaches-7-of (2x+1)/(x+7)

x \to - 7 - lim (\frac{2 x + 1}{x + 7})

\infty

Solution steps

x \to - 7 - lim (\frac{2 x + 1}{x + 7})

\frac{2 x + 1}{x + 7} = (2 x + 1) \frac{1}{x + 7}

= x \to - 7 - lim ((2 x + 1) \frac{1}{x + 7})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to - 7 - lim (2 x + 1) \cdot x \to - 7 - lim (\frac{1}{x + 7})

x \to - 7 - lim (2 x + 1) = - 13

x \to - 7 - lim (\frac{1}{x + 7}) = - \infty

= (- 13) (- \infty)

Apply Infinity Property:

- c \cdot (- \infty) = \infty

= \infty

x \to \infty lim (9 x)

x \to 0 lim (x + sin (x))

x \to 0 + lim (x ln (tan (4 x)))

x \to 0 lim (\frac{x - sin ( 3 x )}{x})

x \to 3 - lim (ln (\frac{1}{x - 3}))

What is the limit as x approaches-7-of (2x+1)/(x+7) ?
The limit as x approaches-7-of (2x+1)/(x+7) is infinity