What is the integral from-2 to 3 of (x^2+3x-5) ?

The integral from-2 to 3 of (x^2+3x-5) is -35/6

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integral from-2 to 3 of (x^2+3x-5)

\int_{- 2}^{3} (x^{2} + 3 x - 5) d x

- \frac{35}{6}

Decimal Notation

- 5.83333 \dots

Solution steps

\int_{- 2}^{3} x^{2} + 3 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{3} x^{2} d x + \int_{- 2}^{3} 3 x d x - \int_{- 2}^{3} 5 d x

\int_{- 2}^{3} x^{2} d x = \frac{35}{3}

\int_{- 2}^{3} 3 x d x = \frac{15}{2}

\int_{- 2}^{3} 5 d x = 25

= \frac{35}{3} + \frac{15}{2} - 25

Simplify

\frac{35}{3} + \frac{15}{2} - 25 : - \frac{35}{6}

= - \frac{35}{6}

(2 - x)^{- 1}

4 x e^{x} csc (x)

\int_{0}^{27} x^{- \frac{2}{3}} d x

\int sin^{3} (4 x) cos^{5} (4 x) d x

y = x + e^{x} - \frac{1}{x}

What is the integral from-2 to 3 of (x^2+3x-5) ?
The integral from-2 to 3 of (x^2+3x-5) is -35/6