What is the tangent of x^2+xy+2y^2=58,(-5,-3) ?

The tangent of x^2+xy+2y^2=58,(-5,-3) is y=-13/17 x-116/17

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tangent of x^2+xy+2y^2=58,(-5,-3)

tangent of

x^{2} + x y + 2 y^{2} = 58, (- 5, - 3)

y = - \frac{13}{17} x - \frac{116}{17}

Solution steps

Find the slope of

x^{2} + x y + 2 y^{2} = 58 : \frac{d y}{d x} = \frac{- 2 x - y}{x + 4 y}

Compute the slope of

x^{2} + x y + 2 y^{2} = 58

(- 5, - 3) : m = - \frac{13}{17}

Find the line with slope m=

- \frac{13}{17}

and passing through

(- 5, - 3) : y = - \frac{13}{17} x - \frac{116}{17}

y = - \frac{13}{17} x - \frac{116}{17}

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What is the tangent of x^2+xy+2y^2=58,(-5,-3) ?
The tangent of x^2+xy+2y^2=58,(-5,-3) is y=-13/17 x-116/17