What is the limit as x approaches 0 of 1/(x+x^2) ?

The limit as x approaches 0 of 1/(x+x^2) is diverges

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limit as x approaches 0 of 1/(x+x^2)

x \to 0 lim (\frac{1}{x + x ^{2}})

diverges

Solution steps

x \to 0 lim (\frac{1}{x + x ^{2}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x + x ^{2}}) = \infty

x \to 0 - lim (\frac{1}{x + x ^{2}}) = - \infty

= diverges

x \to 3 + lim (3 - x)

x \to \infty lim (x^{3} \cdot e^{\frac{1}{x ^{3}}} - x^{3})

x \to 0 + lim (e^{\frac{1}{x}} x)

x \to - 7 - lim (f (x))

x \to 1 lim (\frac{2 x - 1}{x - 1})

What is the limit as x approaches 0 of 1/(x+x^2) ?
The limit as x approaches 0 of 1/(x+x^2) is diverges