What is the limit as x approaches 1+of (x+1)/(x^2-1) ?

The limit as x approaches 1+of (x+1)/(x^2-1) is infinity

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limit as x approaches 1+of (x+1)/(x^2-1)

x \to 1 + lim (\frac{x + 1}{x ^{2} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{x + 1}{x ^{2} - 1})

Simplify

\frac{x + 1}{x ^{2} - 1} : \frac{1}{x - 1}

= x \to 1 + lim (\frac{1}{x - 1})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\int 2 sin (x) + 3 cos (x) d x

y^{^{''}} + y^{^{'}} - 6 y = 0, y (0) = 1, y^{^{'}} (0) = - 13

\int_{0}^{1} x (x - x^{2}) d x

\int \frac{x - 3}{( 3 x - 2 ) ^{2}} d x

x \to - 2 - lim (\frac{x ^{2}}{x ^{2} - 4})

What is the limit as x approaches 1+of (x+1)/(x^2-1) ?
The limit as x approaches 1+of (x+1)/(x^2-1) is infinity