What is the solution for (3+x^2)dy+2*x*y*dx=cos(x)dx ?

The solution for (3+x^2)dy+2*x*y*dx=cos(x)dx is y=(sin(x))/(3+x^2)+(c_{1})/(3+x^2)

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(3+x^2)dy+2xy*dx=cos(x)dx

(3 + x^{2}) d y + 2 \cdot x \cdot y \cdot d x = cos (x) d x

y = \frac{sin ( x )}{3 + x ^{2}} + \frac{c _{1}}{3 + x ^{2}}

Solution steps

(3 + x^{2}) d y + 2 \cdot x \cdot y \cdot d x = cos (x) d x

Solve linear ODE:

y = \frac{sin ( x )}{3 + x ^{2}} + \frac{c _{1}}{3 + x ^{2}}

y = \frac{sin ( x )}{3 + x ^{2}} + \frac{c _{1}}{3 + x ^{2}}

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f (x) = \frac{1}{2} (7 x^{2} + x)^{- 3}

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What is the solution for (3+x^2)dy+2*x*y*dx=cos(x)dx ?
The solution for (3+x^2)dy+2*x*y*dx=cos(x)dx is y=(sin(x))/(3+x^2)+(c_{1})/(3+x^2)