What is the integral from 1 to 2 of x^{1/2} ?

The integral from 1 to 2 of x^{1/2} is (4*2^{1/2}-2)/3

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integral from 1 to 2 of x^{1/2}

\int_{1}^{2} x^{\frac{1}{2}} d x

\frac{4 \cdot 2 ^{\frac{1}{2}} - 2}{3}

Decimal Notation

1.21895 \dots

Solution steps

\int_{1}^{2} x^{\frac{1}{2}} d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{2}

= [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{2}

Compute the boundaries:

\frac{4 \cdot 2 ^{\frac{1}{2}}}{3} - \frac{2}{3}

= \frac{4 \cdot 2 ^{\frac{1}{2}}}{3} - \frac{2}{3}

Simplify

= \frac{4 \cdot 2 ^{\frac{1}{2}} - 2}{3}

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What is the integral from 1 to 2 of x^{1/2} ?
The integral from 1 to 2 of x^{1/2} is (4*2^{1/2}-2)/3