What is (\partial)/(\partial x)(8/x) ?

The answer to (\partial)/(\partial x)(8/x) is -8/(x^2)

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(\partial)/(\partial x)(8/x)

\frac{\partial}{\partial x} (\frac{8}{x})

- \frac{8}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{8}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 1 \cdot x^{- 1 - 1})

Simplify

8 (- 1 \cdot x^{- 1 - 1}) : - \frac{8}{x ^{2}}

= - \frac{8}{x ^{2}}

x \to 0 lim (\frac{x ^{5} + 8 x}{x})

\int_{0}^{1} e^{x} + e^{- x} d x

\frac{d}{d t} (ln ((\frac{a + b t}{a - b t})^{\frac{1}{2}}))

arctan (9 t)

\int_{0}^{2} x^{2} e^{- 9 x} d x

What is (\partial)/(\partial x)(8/x) ?
The answer to (\partial)/(\partial x)(8/x) is -8/(x^2)