What is the derivative of-cos(θ) ?

The derivative of-cos(θ) is sin(θ)

What is the first derivative of-cos(θ) ?

The first derivative of-cos(θ) is sin(θ)

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derivative of

- cos (θ)

sin (θ)

Solution steps

\frac{d}{d θ} (- cos (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d θ} (cos (θ))

Apply the common derivative:

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= - (- sin (θ))

Simplify

= sin (θ)

g (x) = (6 x^{4} + 9)^{2} (x^{3} - 4 x)^{3}

\int 7 x^{15} e^{- x^{8}} d x

\int_{1}^{3} \frac{5}{y} d y

x^{2} y^{^{'}} + x (x + 2) y = x

\int \frac{9 sin ( x ) + 2 sec ( x )}{tan ( x )} d x

What is the derivative of-cos(θ) ?
The derivative of-cos(θ) is sin(θ)
What is the first derivative of-cos(θ) ?
The first derivative of-cos(θ) is sin(θ)