What is the limit as x approaches 0 of (4x^2-x)/(2x) ?

The limit as x approaches 0 of (4x^2-x)/(2x) is -1/2

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limit as x approaches 0 of (4x^2-x)/(2x)

x \to 0 lim (\frac{4 x ^{2} - x}{2 x})

- \frac{1}{2}

Decimal

- 0.5

Solution steps

x \to 0 lim (\frac{4 x ^{2} - x}{2 x})

Simplify

\frac{4 x ^{2} - x}{2 x} : \frac{1}{2} (4 x - 1)

= x \to 0 lim (\frac{1}{2} (4 x - 1))

Plug in the value

x = 0

= \frac{1}{2} (4 \cdot 0 - 1)

Simplify

= - \frac{1}{2}

x \to 4 lim (\frac{x}{x})

x \to \frac{2 π}{3} - lim (- csc (2 x))

x \to 0 lim (\frac{1 0 ^{x} - 4 ^{x}}{x})

x \to - 1 lim (x^{2} + 7 x + 2)

x \to 3 + lim (\frac{x - 3}{9 - x ^{2}})

What is the limit as x approaches 0 of (4x^2-x)/(2x) ?
The limit as x approaches 0 of (4x^2-x)/(2x) is -1/2