What is (\partial)/(\partial x)(x^2-3y^2-2) ?

The answer to (\partial)/(\partial x)(x^2-3y^2-2) is 2x

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(\partial)/(\partial x)(x^2-3y^2-2)

\frac{\partial}{\partial x} (x^{2} - 3 y^{2} - 2)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - 3 y^{2} - 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (3 y^{2}) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3 y^{2}) = 0

\frac{\partial}{\partial x} (2) = 0

= 2 x - 0 - 0

Simplify

= 2 x

arctan (x^{2}), 0

\frac{d}{d x} (lo g_{a} (- x^{2} - x))

\frac{d}{d x} ((e^{3 x} - 1)^{5})

y = ln (ln (\frac{1}{x}))

f (x) = 2 x^{2} + 8 x - 2

What is (\partial)/(\partial x)(x^2-3y^2-2) ?
The answer to (\partial)/(\partial x)(x^2-3y^2-2) is 2x