What is the limit as x approaches 1-of e^{(1/(x^2-1))} ?

The limit as x approaches 1-of e^{(1/(x^2-1))} is 0

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limit as x approaches 1-of e^{(1/(x^2-1))}

x \to 1 - lim (e^{(\frac{1}{x ^{2} - 1})})

0

Solution steps

x \to 1 - lim (e^{\frac{1}{x ^{2} - 1}})

Apply the Limit Chain Rule:

0

= 0

x \to - 2 lim (x^{2} - 2 x - 1)

x \to \infty lim (x, x)

x \to - 3 - lim (\frac{2}{x + 3})

x \to 1 lim (\frac{ln ( x )}{4 ^{l n (x)} - x})

x \to 0 + lim (1 + e^{\frac{1}{x}})

What is the limit as x approaches 1-of e^{(1/(x^2-1))} ?
The limit as x approaches 1-of e^{(1/(x^2-1))} is 0