What is the limit as x approaches infinity of sqrt(4x^2+2x)+2x ?

The limit as x approaches infinity of sqrt(4x^2+2x)+2x is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches infinity of sqrt(4x^2+2x)+2x

x \to \infty lim (4 x^{2} + 2 x + 2 x)

\infty

Solution steps

x \to \infty lim (4 x^{2} + 2 x + 2 x)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (4 x^{2} + 2 x) + x \to \infty lim (2 x)

x \to \infty lim (4 x^{2} + 2 x) = \infty

x \to \infty lim (2 x) = \infty

= \infty + \infty

Apply Infinity Property:

\infty + \infty = \infty

= \infty

x \to 0 + lim (e^{x} + x)

x \to \infty lim (0 xx)

x \to 0 lim (x^{2} cot (4 x^{2}))

x \to 0 lim (sin (\frac{x}{2}))

x \to 3 lim (\frac{e ^{x}}{x - 3})

What is the limit as x approaches infinity of sqrt(4x^2+2x)+2x ?
The limit as x approaches infinity of sqrt(4x^2+2x)+2x is infinity