What is the solution for (d^2)/(dx^2)y+25y=0 ?

The solution for (d^2)/(dx^2)y+25y=0 is y=c_{1}cos(5x)+c_{2}sin(5x)

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(d^2)/(dx^2)y+25y=0

\frac{d ^{2}}{d x ^{2}} y + 25 y = 0

y = c_{1} cos (5 x) + c_{2} sin (5 x)

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 25 y = 0

Solve linear ODE:

y = c_{1} cos (5 x) + c_{2} sin (5 x)

y = c_{1} cos (5 x) + c_{2} sin (5 x)

\int \frac{1}{( x - 7 ) ( x + 1 )} d x

\frac{\partial}{\partial x} (6 + \frac{3}{x} + \frac{6}{x ^{2}})

(x + y e^{\frac{y}{x}}) d x = x e^{\frac{y}{x}} d y

\frac{d}{d x} (e^{3 l n (x^{2})})

x \to 4 lim (- 2 x)

What is the solution for (d^2)/(dx^2)y+25y=0 ?
The solution for (d^2)/(dx^2)y+25y=0 is y=c_{1}cos(5x)+c_{2}sin(5x)