What is the limit as x approaches-8+of 1/((x+8)^2) ?

The limit as x approaches-8+of 1/((x+8)^2) is infinity

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limit as x approaches-8+of 1/((x+8)^2)

x \to - 8 + lim (\frac{1}{( x + 8 ) ^{2}})

\infty

Solution steps

x \to - 8 + lim (\frac{1}{( x + 8 ) ^{2}})

For

x

approaching

- 8

from the right

, x > - 8 \Rightarrow (x + 8)^{2} > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

x \to 0 + lim (2 x + 1)

x \to - 2 + lim (- x)

x \to \infty lim (- 3, + x)

x \to \infty lim (5 + x)

x \to 0 lim (- 2 x ln^{2} (x))

What is the limit as x approaches-8+of 1/((x+8)^2) ?
The limit as x approaches-8+of 1/((x+8)^2) is infinity