What is the integral of (1/((x-7)^2)) ?

The integral of (1/((x-7)^2)) is -1/(x-7)+C

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integral of (1/((x-7)^2))

\int (\frac{1}{( x - 7 ) ^{2}}) d x

- \frac{1}{x - 7} + C

Solution steps

\int \frac{1}{( x - 7 ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - \frac{1}{u}

Substitute back

u = x - 7

= - \frac{1}{x - 7}

Add a constant to the solution

= - \frac{1}{x - 7} + C

x \to 0 lim (sin (- x^{2}))

\int π (x^{2} - x^{4}) d x

3 t^{2} - 3

\int \frac{y}{e ^{2 y}} d y

x \to - 1 lim (x^{2} + 2)

What is the integral of (1/((x-7)^2)) ?
The integral of (1/((x-7)^2)) is -1/(x-7)+C