What is the solution for y^{''}+y^'-72y=0 ?

The solution for y^{''}+y^'-72y=0 is y=c_{1}e^{8t}+c_{2}e^{-9t}

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y^{''}+y^'-72y=0

y^{^{''}} + y^{^{'}} - 72 y = 0

y = c_{1} e^{8 t} + c_{2} e^{- 9 t}

Solution steps

y^{''} (t) + y^{'} (t) - 72 y = 0

Solve linear ODE:

y = c_{1} e^{8 t} + c_{2} e^{- 9 t}

y = c_{1} e^{8 t} + c_{2} e^{- 9 t}

x \to 2 - lim (\frac{2 x}{x - 1})

\frac{\partial}{\partial x} (2 sin (x))

\frac{d y}{d x} = e^{3 x} + 8 y

\int - \frac{2}{x ^{2}} d x

\int_{- 4}^{4} (e^{x} - e^{- x})^{2} d x

What is the solution for y^{''}+y^'-72y=0 ?
The solution for y^{''}+y^'-72y=0 is y=c_{1}e^{8t}+c_{2}e^{-9t}