What is the limit as x approaches 1 of-4/(x-1) ?

The limit as x approaches 1 of-4/(x-1) is diverges

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limit as x approaches 1 of-4/(x-1)

x \to 1 lim (- \frac{4}{x - 1})

diverges

Solution steps

x \to 1 lim (- \frac{4}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (- \frac{4}{x - 1}) = - \infty

x \to 1 - lim (- \frac{4}{x - 1}) = \infty

= diverges

x \to \infty lim (\frac{3 x ^{2}}{x + 1} - \frac{x ^{3}}{x ^{2} + 1})

x \to \infty lim ((x^{2} + 1)^{\frac{1}{x ^{2}}})

x \to \infty lim ((- 3)^{n})

x \to 0 + lim (3 e^{x} + cos (2 x))

x \to 0 lim (\frac{x + 12}{x + 6})

What is the limit as x approaches 1 of-4/(x-1) ?
The limit as x approaches 1 of-4/(x-1) is diverges