What is (\partial)/(\partial x)(x^2-2y^2) ?

The answer to (\partial)/(\partial x)(x^2-2y^2) is 2x

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(\partial)/(\partial x)(x^2-2y^2)

\frac{\partial}{\partial x} (x^{2} - 2 y^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - 2 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 2 x - 0

Simplify

= 2 x

\frac{\partial}{\partial x} (\frac{x ^{2} y ^{2}}{x + y})

\int \frac{5 x 4 6 x ^{2} + 5}{4} d x

\frac{\partial}{\partial x} (30 x^{4} y^{5} + 24 x^{5} y^{7})

f (x) = \frac{1}{( x - 2 )}

cos (a^{9} + x^{9})

What is (\partial)/(\partial x)(x^2-2y^2) ?
The answer to (\partial)/(\partial x)(x^2-2y^2) is 2x