What is the limit as x approaches infinity of-x^{-1} ?

The limit as x approaches infinity of-x^{-1} is 0

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limit as x approaches infinity of-x^{-1}

x \to \infty lim (- x^{- 1})

0

Solution steps

x \to \infty lim (- x^{- 1})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to \infty lim (x^{- 1})

x \to a lim [f (x)]^{b} = [x \to a lim f (x)]^{b}

With the exception of indeterminate form

= - (x \to \infty lim (x))^{- 1}

Apply the common limit:

x \to \infty lim (x) = \infty

= - \infty^{- 1}

Apply Infinity Property:

\infty^{- c} = 0

= 0

x \to 0 lim (\frac{- e ^{x}}{x ^{2}})

x \to - 1 + lim (\frac{∣ x + 1 ∣}{x + 1})

x \to 0 lim (cos (x) \frac{1}{x})

x \to 7 lim (x - 2)

x \to 0 lim (f (a x))

What is the limit as x approaches infinity of-x^{-1} ?
The limit as x approaches infinity of-x^{-1} is 0