What is the limit as x approaches-3 of (4x)/(9-x^2) ?

The limit as x approaches-3 of (4x)/(9-x^2) is diverges

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limit as x approaches-3 of (4x)/(9-x^2)

x \to - 3 lim (\frac{4 x}{9 - x ^{2}})

diverges

Solution steps

x \to - 3 lim (\frac{4 x}{9 - x ^{2}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 3 + lim (\frac{4 x}{9 - x ^{2}}) = - \infty

x \to - 3 - lim (\frac{4 x}{9 - x ^{2}}) = \infty

= diverges

x \to - 2 lim (\frac{8 + 4 x}{2 + x})

x \to - 1 + lim (\frac{x ^{2}}{x ^{2} - 1})

x \to 1 lim (3 x - 3)

x \to 2 - lim (\frac{x + 3}{x + 2})

x \to - 1 lim (4 x + 5)

What is the limit as x approaches-3 of (4x)/(9-x^2) ?
The limit as x approaches-3 of (4x)/(9-x^2) is diverges