What is the limit as x approaches 1 of 2^{2/(x-1)} ?

The limit as x approaches 1 of 2^{2/(x-1)} is diverges

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limit as x approaches 1 of 2^{2/(x-1)}

x \to 1 lim (2^{\frac{2}{x - 1}})

diverges

Solution steps

x \to 1 lim (2^{\frac{2}{x - 1}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (2^{\frac{2}{x - 1}}) = \infty

x \to 1 - lim (2^{\frac{2}{x - 1}}) = 0

= diverges

x \to 1 lim (3 x^{2} - 2 x - 1)

x \to 0 lim (x^{2 x + 1})

x \to 0 lim (\frac{x ^{2} + x}{4 x})

x \to 1 lim ((2 - x)^{4 t a n (\frac{π}{2} x)})

x \to - 1 lim (\frac{( x - 1 )}{x + 1})

What is the limit as x approaches 1 of 2^{2/(x-1)} ?
The limit as x approaches 1 of 2^{2/(x-1)} is diverges