What is the sum from n=0 to infinity of 8(-1/2)^n ?

The sum from n=0 to infinity of 8(-1/2)^n is converges

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sum from n=0 to infinity of 8(-1/2)^n

n = 0 \sum \infty 8 (- \frac{1}{2})^{n}

converges

Solution steps

n = 0 \sum \infty 8 (- \frac{1}{2})^{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 8 \cdot n = 0 \sum \infty (- \frac{1}{2})^{n}

Apply Series Ratio Test:

converges

= 8 converges

= converges

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What is the sum from n=0 to infinity of 8(-1/2)^n ?
The sum from n=0 to infinity of 8(-1/2)^n is converges