What is the limit as x approaches 0 of 1/(x^2)+ln(x) ?

The limit as x approaches 0 of 1/(x^2)+ln(x) is Does not exist

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limit as x approaches 0 of 1/(x^2)+ln(x)

x \to 0 lim (\frac{1}{x ^{2}} + ln (x))

Does not exist

Solution steps

x \to 0 lim (\frac{1}{x ^{2}} + ln (x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x ^{2}} + ln (x)) = \infty

x \to 0 - lim (\frac{1}{x ^{2}} + ln (x)) =

Does not exist

= Does not exist

x \to 2 lim ((1 + \frac{1}{x})^{x})

x \to 0 lim (\frac{x}{x ^{4}})

x \to \frac{π}{2} lim ((\frac{π}{cos ( x )}) - 2 x tan (x))

x \to \infty lim (\frac{5 ^{x + 1}}{e ^{x}})

x \to \infty lim (6 x e^{- x})

What is the limit as x approaches 0 of 1/(x^2)+ln(x) ?
The limit as x approaches 0 of 1/(x^2)+ln(x) is Does not exist