What is the sum from n=3 to infinity of 1/((2n-5)^3) ?

The sum from n=3 to infinity of 1/((2n-5)^3) is converges

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sum from n=3 to infinity of 1/((2n-5)^3)

n = 3 \sum \infty \frac{1}{( 2 n - 5 ) ^{3}}

converges

Solution steps

n = 3 \sum \infty \frac{1}{( 2 n - 5 ) ^{3}}

Apply Series Integral Test:

converges

= converges

t^{2} sin (t)

\int_{2}^{3} \frac{3}{x} d x

\frac{\partial}{\partial x} (\frac{8 x}{x ^{2} + 6 y ^{2}})

\int 13 tan^{3} (θ) d θ

x \to 0 lim (\frac{9 + x}{x})

What is the sum from n=3 to infinity of 1/((2n-5)^3) ?
The sum from n=3 to infinity of 1/((2n-5)^3) is converges