What is the limit as x approaches pi of cos(2x) ?

The limit as x approaches pi of cos(2x) is 1

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limit as x approaches pi of cos(2x)

x \to π lim (cos (2 x))

1

Solution steps

x \to π lim (cos (2 x))

Plug in the value

x = π

= cos (2 π)

Simplify

cos (2 π) : 1

= 1

x \to - 2 lim (\frac{2}{x ^{2} - 4})

x \to - \infty lim (1 - x^{2})

x \to 0 + lim (x^{2} \cdot ln (4 x^{2}))

x \to 0 - lim (e^{\frac{1}{x}} - 1)

t \to 0 lim (\frac{2 sin ( 4 t )}{t})

What is the limit as x approaches pi of cos(2x) ?
The limit as x approaches pi of cos(2x) is 1