What is the limit as x approaches 6+of ln(x^2-36) ?

The limit as x approaches 6+of ln(x^2-36) is -infinity

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limit as x approaches 6+of ln(x^2-36)

x \to 6 + lim (ln (x^{2} - 36))

- \infty

Solution steps

x \to 6 + lim (ln (x^{2} - 36))

Apply the Limit Chain Rule:

- \infty

= - \infty

y^{^{'}} + x y = x

y = 7 e^{1 - x^{2}}, at

\frac{d}{d x} ((1 - \frac{x}{2})^{e^{x^{2}}})

x \frac{d y}{d x} + (3 x + 1) y = e^{3 x}

(6 y + 2 t - 7) d t + (8 y + 6 t - 1) d y = 0

What is the limit as x approaches 6+of ln(x^2-36) ?
The limit as x approaches 6+of ln(x^2-36) is -infinity