What is the limit as x approaches 1 of-(x^2-4x+8) ?

The limit as x approaches 1 of-(x^2-4x+8) is -5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of-(x^2-4x+8)

x \to 1 lim (- (x^{2} - 4 x + 8))

- 5

Solution steps

x \to 1 lim (- (x^{2} - 4 x + 8))

Plug in the value

x = 1

= - (1^{2} - 4 \cdot 1 + 8)

Simplify

= - 5

x \to 3 + lim (3 x - 3)

x \to 1 lim (9 - x^{2})

x \to \infty lim (e^{9 x l n (1 + \frac{1}{7 x})})

x \to 0 lim (sin (∣ x ∣))

x \to 0 lim (\frac{1}{2 - 2 ^{\frac{1}{x}}})

What is the limit as x approaches 1 of-(x^2-4x+8) ?
The limit as x approaches 1 of-(x^2-4x+8) is -5