What is the limit as n approaches infinity of sin(2pin) ?

The limit as n approaches infinity of sin(2pin) is diverges

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limit as n approaches infinity of sin(2pin)

n \to \infty lim (sin (2 πn))

diverges

Solution steps

n \to \infty lim (sin (2 πn))

Apply Limit Divergence Criterion:

diverges

= diverges

x \to 0 lim (x^{3} - x^{2})

x \to 0 lim ((\frac{x}{1 + x})^{x})

x \to 1 lim (x^{2} + 3 x - 5)

x \to - \infty lim (x + 3 x^{\frac{2}{3}})

x \to 7 lim (\frac{x ^{2} + 3}{x})

What is the limit as n approaches infinity of sin(2pin) ?
The limit as n approaches infinity of sin(2pin) is diverges