What is the limit as x approaches-infinity of e-e^x ?

The limit as x approaches-infinity of e-e^x is e

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limit as x approaches-infinity of e-e^x

x \to - \infty lim (e - e^{x})

e

Decimal Notation

2.71828 \dots

Solution steps

x \to - \infty lim (e - e^{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to - \infty lim (e) - x \to - \infty lim (e^{x})

x \to - \infty lim (e) = e

x \to - \infty lim (e^{x}) = 0

= e - 0

Simplify

= e

x \to 0 + lim ((2 x)^{x^{2}})

x \to 2 lim (e^{- x})

x \to \frac{π}{2} - lim (1 - sin (x))

x \to 0 + lim (x ln (x^{9}))

x \to 0 lim (\frac{tan ( x ) ( ( 1 - cos ( x ) ) )}{xxx})

What is the limit as x approaches-infinity of e-e^x ?
The limit as x approaches-infinity of e-e^x is e