What is (\partial)/(\partial x)(2x+3y-4) ?

The answer to (\partial)/(\partial x)(2x+3y-4) is 2

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(\partial)/(\partial x)(2x+3y-4)

\frac{\partial}{\partial x} (2 x + 3 y - 4)

2

Solution steps

\frac{\partial}{\partial x} (2 x + 3 y - 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (3 y) - \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (3 y) = 0

\frac{\partial}{\partial x} (4) = 0

= 2 + 0 - 0

Simplify

= 2

f (x) \frac{2}{x}

\frac{x ^{2} - 2 x - 3}{( x - 1 ) ^{2}}

144 y^{^{'''}} + 168 y^{^{''}} + 49 y^{^{'}} = 0

\frac{d}{d x} (\frac{3 x}{1 + x ^{2}})

x \frac{d y}{d x} = y + x e^{x}

What is (\partial)/(\partial x)(2x+3y-4) ?
The answer to (\partial)/(\partial x)(2x+3y-4) is 2