What is the integral of 1/(y^{1/2)} ?

The integral of 1/(y^{1/2)} is 2y^{1/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(y^{1/2)}

\int \frac{1}{y ^{\frac{1}{2}}} d y

2 y^{\frac{1}{2}} + C

Solution steps

\int \frac{1}{y ^{\frac{1}{2}}} d y

Apply the Power Rule

: 2 y^{\frac{1}{2}}

= 2 y^{\frac{1}{2}}

Add a constant to the solution

= 2 y^{\frac{1}{2}} + C

\int e^{2 x} sin (e^{2 x}) d x

\int 4 t^{3} + t d t

y = 10000 + 30 x e^{\frac{x}{800}}

y^{^{'}} - \frac{4}{x} y = \frac{y ^{4}}{x ^{8}}

\int_{0}^{y + z} \frac{1}{( z + y + x ) ^{3}} d x