What is the limit as x approaches pi-of ln(x)sin(x) ?

The limit as x approaches pi-of ln(x)sin(x) is 0

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limit as x approaches pi-of ln(x)sin(x)

x \to π - lim (ln (x) sin (x))

0

Solution steps

x \to π - lim (ln (x) sin (x))

Plug in the value

x = π

= ln (π) sin (π)

Simplify

ln (π) sin (π) : 0

= 0

x \to - 1 lim (3 x^{2} + 2 x - 5)

x \to 1 lim (∣ (3 - 4 x) ∣)

x \to - \frac{π}{2} lim (- 4 x - \frac{π}{2})

x \to 0 + lim (\frac{1 + ln ( x )}{x})

x \to \infty lim (x^{2} - 5 x)

What is the limit as x approaches pi-of ln(x)sin(x) ?
The limit as x approaches pi-of ln(x)sin(x) is 0