What is the limit as h approaches 0 of 1/(1+h^2) ?

The limit as h approaches 0 of 1/(1+h^2) is 1

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limit as h approaches 0 of 1/(1+h^2)

h \to 0 lim (\frac{1}{1 + h ^{2}})

1

Solution steps

h \to 0 lim (\frac{1}{1 + h ^{2}})

Plug in the value

h = 0

= \frac{1}{1 + 0 ^{2}}

Simplify

= 1

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What is the limit as h approaches 0 of 1/(1+h^2) ?
The limit as h approaches 0 of 1/(1+h^2) is 1