What is the limit as x approaches 0 of 1/((1-e^x)) ?

The limit as x approaches 0 of 1/((1-e^x)) is diverges

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limit as x approaches 0 of 1/((1-e^x))

x \to 0 lim (\frac{1}{( 1 - e ^{x} )})

diverges

Solution steps

x \to 0 lim (\frac{1}{1 - e ^{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{1 - e ^{x}}) = - \infty

x \to 0 - lim (\frac{1}{1 - e ^{x}}) = \infty

= diverges

x \to 0 - lim (\frac{ln ( x + 1 )}{x})

x \to 2 lim (\frac{3 x + 4}{2 x + 1})

x \to 0 lim (\frac{x + 1}{2 x})

x \to - 3 lim (- 2 x^{2} + 1)

x \to 0 lim (\frac{x}{sec ( x )})

What is the limit as x approaches 0 of 1/((1-e^x)) ?
The limit as x approaches 0 of 1/((1-e^x)) is diverges