What is the limit as x approaches 0-of sqrt(x^2+4) ?

The limit as x approaches 0-of sqrt(x^2+4) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0-of sqrt(x^2+4)

x \to 0 - lim (x^{2} + 4)

2

Solution steps

x \to 0 - lim (x^{2} + 4)

Plug in the value

x = 0

= 0^{2} + 4

Simplify

0^{2} + 4 : 2

= 2

\frac{d}{d x} (e^{- 4 x^{6}})

\frac{d y}{d x} + a y = b

\frac{d}{d x} (ln (\frac{1 - sin ( x )}{1 + sin ( x )}))

n = 0 \sum \infty (\frac{7}{8})^{n}

\frac{\partial}{\partial y} (\frac{z ^{2} + 2 x + y}{x y})

What is the limit as x approaches 0-of sqrt(x^2+4) ?
The limit as x approaches 0-of sqrt(x^2+4) is 2