What is the limit as x approaches 0 of (sin(x)+1)/x ?

The limit as x approaches 0 of (sin(x)+1)/x is diverges

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limit as x approaches 0 of (sin(x)+1)/x

x \to 0 lim (\frac{sin ( x ) + 1}{x})

diverges

Solution steps

x \to 0 lim (\frac{sin ( x ) + 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{sin ( x ) + 1}{x}) = \infty

x \to 0 - lim (\frac{sin ( x ) + 1}{x}) = - \infty

= diverges

x \to 0 lim (\frac{x + 1}{2 ^{x} - 1})

x \to 0 + lim (e^{x} - 1)

x \to 1 lim (\frac{( 3 + x ) ^{2} - 9}{x})

x \to 3 lim (\frac{2 x + 3}{x + 3})

x \to 0 lim (\frac{2 x}{1 + x ^{2}})

What is the limit as x approaches 0 of (sin(x)+1)/x ?
The limit as x approaches 0 of (sin(x)+1)/x is diverges